Sin(A + B) = sinAcosB + cosAsinB
cos(A + B) = cosAcosB - sinAsinB
If sinA = ⅗ and sinB = 5/13 where both angles A & B are in quadrant II. Find sin(A + B).
sinA = ⅗ & cosA = -⅘ and sinB = 5/13 & cosB = -12/13
sin(A + B) = (⅗)(-12/13) + (-⅘)(5/13) = (-36/65) + (-20/65) = -56/65

USING THIS INFORMATION FIND cos(A+B)

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

step-by-step explanation:

what is

step-by-step explanation:

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.