6. A triangle in the unit circle has a central angle that is 140°, determine the coordinates of

the point that is in Quadrant II.

(-0.198, 0.98).

Step-by-step explanation:

So, in this question we are given the following parameters or information or data that is going to assist us in determining the solution to this question. So, we have that;

" A triangle in the unit circle has a central angle that is 140°"

Hence, we are to determine the point that is in Quadrant II. So, let us dive right into the solution to the question below;

For a unit circle the value for the radius, r = 1. For the x, we have that;

x = r × cos φ and for y (1).

x = 1 × cos 140° = cos 140° = - 0.198.

For y, we have that y = r × sin φ. (2).

y = 1 × sin 140° = sin 140° = 0.98.

Hence, the point that is in Quadrant II = (x,y) = (- 0.198, 0.98).

Please Note that your calculator is in radians(rad).

1/800 is the right answer

a orange at the grocery store idk what other product that could be