5) What is the pressure of a 3 moles of oxygen in a 5 liter container at 300
degrees K. *
1500 atm
14.76 atm
369 atm
0 24.6

1496.52 Pa, 14.76 atm

Step-by-step explanation:

This question can be solved using ideal gas law

according to which

pv = nrt

where p is the pressure of gas

v is volume of gas

n is amount gas in moles

R is ideal gas constant whose value is 8.314 J/mol

T is absolute temperature of gas on Kelvin scale

given

v = 5 liter

n = 3

T = 300 kelvin

R = 8.314 J/mol

Let the pressure be p

Substituting the above value in ideal gas law equation we have

p*5 = 3*8.314*300

p = 7482.6/5 = 1496.52 Pa

This pressure is in pascal while option is in atm

we know 1 Pascal is equal to 0.0000098692 atm

we know that 1 Atm = 101325 Pa

thus, 1496.52 is equal to  0.0000098692*1496.52 atm

1496.52 is equal to 14.76 atm

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step-by-step explanation:

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