Vicente has a prism-like water tank whose base area is 1.21.21, point, 2 square meters. He bought 666 goldfish at the store, and the store owner told him to make sure their density in the tank isn't more than 444 fish per cubic meter. Vicente needs to figure out how high to fill the water in the tank.
What is the lowest possible height so the fish aren't too crowded?

We have been given that Vicente has a prism-like water tank whose base area is 1.2 square meters. He bought 6 goldfish at the store, and the store owner told him to make sure their density in the tank isn't more than 4 fish per cubic meter.

First of all, we will find volume of water needed for 6 fishes using proportion.

We know that volume of prism is base area times height.

Therefore, the lowest possible height would be 1.25 meters.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: