1/5 of the shoes in a factory are green. If you pick a shoe, replace it, pick another shoe and replace it, and pick a third shoe, what is the probability that none of the shoes are green?

The probability that none of the three shoes selected are green = 64/125

Step-by-step explanation:

If we have 1/5 of shoes being green, then the number of non-green shoes = 1-1/5 = 4/5

Now, this is a probability with replacement.

probability of the first shoe since it’s not green = 4/5

probability of second shoes since it’s not green = 4/5

probability of third shoe since it’s not green = 4/5

Now, the probability that none of the shoes are green = 4/5 * 4/5 * 4/5 = 64/125

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

da freeck kinda math is this just drop out

step-by-step explanation: