The cost of fuel to propel a boat through the water (in dollars per hour) is proportional to the cube of the speed. A certain ferry boat uses worth of fuel per hour when cruising at miles per hour. Apart from fuel, the cost of running this ferry (labor, maintenance, and so on) is per hour. At what speed should it travel so as to minimize the cost per mile traveled?

The correct answer to the following question will be "V = 15 mph".

Step-by-step explanation:

According to the question,

C(V) ∝ V³

then,

C(V) = KV³

When, C = 100 and V = 10

then,

⇒        

∴  

As we know,

Total cost per hour,

C₁

Cost per mile =

Now,

C₂ =

⇒  =

Then we'll need to discover their derivative as well as set that to zero (0) to minimize it.

⇒  

⇒  

On applying cross-multiplication, we get

⇒  

⇒  

So that the cost is minimum at "V = 15 mph".

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!

3/20

step-by-step explanation:

well, there are 20 outcomes, and 3 of them you want. so, 3/20