One number is 16 more than another number. The two numbers have a sum of 120. Which system of equations could you use to find the two numbers?

y = x-16

y = -x+ 120

Step-by-step explanation:

Let one number be x

let other number be y .

It is given that other number is 16 more than other number.

Let x be the greater number then

Then x will be 16 more than y.

Mathematical equation for this will be

x = y+16

subtracting 16 from both sides

x-16 = y+16 -16

=> x-16 = y

Thus first equation is y = x-16.

It is given that sum of both number is 120.

Thus, sum of x and y is 120

Mathematical equation for this will be

x+y = 120

y = 120 -x  

rearranging x and 120 we have

y = -x +120

Thus, second equation is y = -x+ 120.

system of required equation is

y = x-16

y = -x+ 120

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6