The table below describes band members at Mike’s school. Band Member Knowledge of Instruments Can Only Play One Instrument Can Play More than One Instrument Grade 6 15 6 Grade 7 20 8 Grade 8 18 7 Mike used the computation StartFraction 7 Over (6 + 8 + 7) almost-equals 0.33 = 33 percent to find the percentage of eighth-grade band members who can play more than one instrument. What error did Mike make? Mike included 7 when finding a sum to use as the denominator of his fraction. Mike used the total of the column containing 7 as his denominator instead of the total of the row containing 7. Mike should have used the sum of all the cell values as his denominator. Mike should have used the number of eighth-grade students who can only play one instrument as the denominator of his fraction.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: