**Marking Brainliest** Which of the following are point-slope equations of the line going through (-4, 6) and (1, 2)? Check all that apply.

A: y - 6 = -5/4(x+4)

E: y-2 =  -5/4(x-1)

Step-by-step explanation:

If there is a point (x1,y1) on coordinate plane and slope is m then  point-slope form of equation is given by

y-y1 = m(x-x1).

We also know that if there are two point  (x1,y1) and (x2,y2) on coordinate plane then its slope is given by

slope m = (x1-x2)/(y1-y2).

Given that

points are  (-4, 6) and (1, 2).

then slope m = (-4 -1)/(6-2) = -5/4

thus, slope m for required line is -5/4

Now , that we have two points   (-4, 6) and (1, 2). Both can be used to get point-slope equations.

using point slope equation form expression y-y1 = m(x-x1)

we have

1. point-slope equation for (-4, 6)

y - 6 = -5/4(x-(-4))

=> y - 6 = -5/4(x+4)

2. point-slope equation for (1,2)

y-2 =  -5/4(x-1)

Thus, option A: y - 6 = -5/4(x+4) is one solution

option E: y-2 =  -5/4(x-1) is another solution.

step-by-step explanation:

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation