Solve for the zeros of the quadratic function f(x) = 9x2 + 6x + 1. Write the answer as a fraction. x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction x = StartFraction negative 6 plus or minus StartRoot (negative 6) squared minus 4 (9)(1) EndRoot Over 2(9) EndFraction x = StartFraction negative 6 plus or minus StartRoot 36 minus 36 EndRoot Over 18 EndFraction

f|_|(k, $hiī, +i+s, bi+ch

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step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.