Factor to solve each equation. Does the equation have a solution of x = 2? Select Yes or No for each.

4x^2 - 16 = 0

<=> (2x)^2 - 4^2 = 0

<=> (2x + 4)(2x - 4) = 0

<=> x = -2 or x = 2

=> YES

x^2 - 4x + 4 = 0

<=> (x - 2)^2 = 0

<=> x = 2

=> YES

4x^2 + 16x + 16 = 0

<=> 4(x^2 + 4x + 4) = 0

<=> 4(x + 2)^2 = 0

<=> x = -2

=> NO

Hope this helps!

:)

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic