2x + y 2 =6
3x-2y2 = -5

  (x, y) = (1, ±2)

Step-by-step explanation:

To solve this pair of equations, one can add the second equation to twice the first:

  2(2x +y^2) +(3x -2y^2) = 2(6) +(-5)

  4x +3x = 12 -5 . . . . simplify a bit

  7x = 7 . . . . . . . . . . . collect terms

  x = 1  . . . . . . . . . . . . divide by 7

Then y can be found from the first equation:

  y^2 = 6 -2x = 6 -2(1) = 4

  y = ±√4 = ±2

The solutions are ...

  (x, y) = (1, -2)   or   (1, 2)

step-by-step explanation:

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.