The circle below is centered at (3, 1) and has a radius of 2. What is its equation? HA A. (x-3)2 + (y - 1)2 = 2 B. (x - 1)2 + (y - 3)2 = 4 C. (x-1)2 + (y - 3)2 = 2 D. (x-3)2 + (- 1)2 = 4 Help
Write an equation of the line that passes through the point (2, 3) and is perpendicular to the line x = -1. a) y = 1 b) y = 3 c) y = 0 eliminate d) y = -3