What is the inverse of the logarithmic function

f(x) = loggx?

f-1(x) = x

8-1(x) = -logo

f-1(x) = 9x

F-1(x) =

log, x

9^x

Step-by-step explanation:

I guess we have the function:

f(x) = log₉(x)

The inverse function of this will be the base of the logaritm (9 in this case) powered with the thing inside the logaritm ( in this case x)

Then the inverse is f-1(x) = 9^x

right

step-by-step explanation: