You are driving on a hot day when your car overheats and stops running. The car overheats at 280°F and can be driven again at 230°F. When it is 80°F outside, the cooling rate of the car is r is equal to 0 point 0 0 5 8 $r=0.0058$ r=0.0058 . How long do you have to wait until you can continue driving? Use Newton's Law of Cooling to solve the problem. Round your answer to the nearest whole minute.

50 minutes

Step-by-step explanation:

Given the following :

Overheating temperature T0 = 280°F

Driving temperature T = 230°F

Ourltside temperature TR = 80

Cooling rate r = 0.0058

Using Newtons law of cooling

T = (T0 - TR)e^(-0.0058t) + 80

230 = 200e^(-0.0058t) + 80

150 = 200e^(-0.0058t)

(150/200) = e^(-0.0058t)

0.75 = e^(-0.0058t)

In 0.75 = (-0.0058t)

-0.2877 = -0.0058t

t = - 0.2877/0.0058

t = 49.60

t = 50 minutes (to the nearest whole number)

omg what happend to your question? if you could edit this question i can

step-by-step explanation:

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1