The graphed line shown below is y = negative 4 x minus 12.

On a coordinate plane, a line goes through (negative 3, 0) and (negative 2, negative 4).

Which equation, when graphed with the given equation, will form a system that has no solution?
y = 4 x + 12
y = negative 4 x
y = negative 12
y = negative 4 (x + 3)

Which equation, when graphed with the given equation, will form a system that has an infinite number of solutions?

y + 1 = 3 x

y = negative 3 x + 1

y = 3 x + 1

y minus 3 x = negative 3

Mark this and return

Step-by-step explanation:

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches