Use the graph of the function y = –x2 + 2x + 8 to determine the solutions of the quadratic equation 0 = –x2 + 2x + 8. What are the solutions of the quadratic equation 0 = –x2 + 2x + 8? –4 and 2 –2 and 8 –2 and 4 4 and 8

As given in the equation

y=-x^2+2x+8

-x^2+2x+8=0

-x^2+4x-2x+8=0

-x(x-4)-2(x-4)=0

(-x-2)(x-4)=0

x=4 and x=-2

So,option C is correct,the -2 and 4 is the solution of this equation.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier