Please find the area of the shaded region i appreciate your help

(4/3) π units²  or  (b):  33.5 units²

Step-by-step explanation:

The area of a sector of a circle of radius r and central angle Ф is a fraction of the total area of the circle:  (Ф/[2π]) * πr².

Here we find the area of the circle to be A = π (8 units)².

                                                    60

Multiply that by the fraction   , or 1/6

                                                    360

We get:  (1/6) (π (8 units)² = (4/3) π units², or approximately 33.5 units²

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

20 feet per second

hope i

-lavira : )