1. Solve the equation x13 - 2x12 - x11 + 2x10 = 0 in the real number system.
A X=0 with multiplicity 10, x = -1, x = 1, x = 2
B x=0 with multiplicity 10. X = -1, x = 2 with multiplicity 2
Cx= -1, x = 1, x = 2
DX=0 with multiplicity 10, x= -1 X = 1 with multiplicity 2

the answer is true.

step-by-step explanation:

what am i trying to find out. you didn't put up the whole question.

step-by-step explanation:

a and c

for infinitely many solutions we require both left and right sides to be equal

distribute and simplify

a

14 - 8x = 20 - 8x - 6 = 14 - 8x ← both sides equal so infinite solutions

b

6x - 54 = 6x - 54 + x = 7x - 54 ← not equal

c

4x + 16 = 4x + 10 + 6 = 4x + 16 ← both sides equal so infinite solutions

d

5x - 40 + 10 = 5x + 10

5x - 30 = 5x + 10 ← not equal