Ma poate ajuta cineva la acesta problema: pe o drepta g considerati punctele D, R, P si T coliniare in aceasta ordine astfel incat DR=PT=3 cm, iar RP=4cm

Givens

and

Points D, R, P and T are collinear.

The image attached shows a representation of this problem.

By sum of segments, we have

Replacing all given values, we have

Therefore, the segment DT is 10 centimeters long.

Now, we know that point E is the center of segment RP, which means is a middle point, divides the segment equally. So, to prove that segment DT is symmetrical regarding point E, we need to prove that both sides are equal.

, by definition of middle point.

By sum of segments, we have

Which means .

Therefore, segment DT is symmetrical regarding point E.

gdp is the best phrase!

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2