The units pf the digits of a two digits numeral is 8 if the digits are reversed the new number is 18 greater than the oringal number fund the oringal numeral

complete question:

The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?

The original number is 10a + b  = 10 × 3 + 5  = 35

Step-by-step explanation:

Let

the number = ab

a occupies the tens place while b occupies the unit place. Therefore,

10a + b

The sum of the digits of two-digits numeral

a + b = 8(i)

If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.

Therefore,

10b + a = 18 + 10a + b

10b - b + a - 10a = 18

9b - 9a = 18

divide both sides by 9

b - a = 2(ii)

a + b = 8(i)

b - a = 2(ii)

b = 2 + a from equation (ii)

Insert the value of b in equation (i)

a + (2 + a) = 8

2a + 2 = 8

2a = 6

a = 6/2

a = 3

Insert the value of a in equation(ii)

b - 3 = 2

b = 2 + 3

b = 5

The original number is 10a + b  = 10 × 3 + 5  = 35

answer: options?

step-by-step explanation:

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1