If we draw a ball from an urn containing 10 numbered balls, with seven red balls that are numbered 1, 2, 3, 4, 5, 6, 7 and three that are green and are numbered 8, 9, 10, what is the probability of drawing a ball that is red and odd?

Step-by-step explanation:

Total balls = 10

Odd red balls = 1 3 5 7 so 4 balls

Probability of odd and red ball = 4/10 = 2/5

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.