Chelsea has $45 to spend at the fair. She spends $20 on admission and $15 on snacks. She wants to play a game that costs $0.65 per game. Write an inequality to find the maximum number of times, x, Chelsea can play the game. Using this inequality, determine the maximum number of times she can play the game.

15 games

Step-by-step explanation:

Let's find out how much money Chelsea currently has. To do this, we can do 45-20-15 = $10. Now we know she has $10 left to play the game. We know that Chelsea can't spend more than $10 on the game, so she can spend at most $10. Turning this into an inequality, we get 0.65x≤10. The reason we wrote 0.65 instead of x is because each game costs $0.65. However, in this context, she can't play the game negative times, so our inequality becomes 0≤0.65x≤10. Now, let's solve!

When we divide the inequality by 0.65 (so that we are left with just x), we get 0≤x≤15.4. The maximum number of times she can play has to be an integer (1,2,3..) because you can't play 5.8 games, it's not possible in this context. Therefore, the maximum number of games she can play is 15 because that is the largest integer under 15.4. Hope this helps!

your answer would be 10x - 1

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step-by-step explanation:

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