Find the number of real solutions of the equation x^2+10x+35=0 using the discriminant:(b^2-4ac)

No real roots or solutions

Step-by-step explanation:

X^2+10x+35=0 using this equation you can tell that a=1, b=10, and c=35. Using the numbers for the formula,

b^2 - 4ac, it will look like this... 10^2-4(1)(35). Next step is the exponent. It will look like this now, 100-4(1)(35), the next step is to multiply. 100-140= -40. When the discriminant is negative, there are no real roots, or solutions.

where r the answers

step-by-step explanation:

the correct answer is 1: 2

step-by-step explanation:

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