I need help and it’s question 36 please answer

try putting an imaginary 1 in front of your variable (c). so

1c + 4c = 15

combine like terms

(1c + 4c) = 5c

therefore we have

5c = 15

now, divide BOTH sides of the equation by 5

5c/5 = 15/5

5c/5 = c

15/5 = 3

c=3

where is it you mean 38

Step-by-step explanation:

=1/4

Subtract

3

3

3

from both sides of the equation

2

+

3

=

1

4

2s+3=14s

2s+3=14s

2

+

3

−

3

=

1

4

−

3

2

=

1

4

−

3

Subtract

1

4

14s

14s

from both sides of the equation

2

=

1

4

−

3

2s=14s-3

2s=14s−3

2

−

1

4

=

1

4

−

3

−

1

4

−

1

2

=

−

3

−

1

2

=

−

3

-12s=-3

−12s=−3

−

1

2

−

1

2

=

−

3

−

1

2

=

1

4

ipuy6tygy

step-by-step explanation:

answer: the answer is ann