Solve the following systems algebraically using substitution.

2x - y = 4 r – 3y = -3

x=
y=

x = 3

y = 2

Step-by-step explanation:

2x - y = 4

y = 2x - 4

I'm going to assume the r is an x

x - 6x + 12 = -3

-5x = -15

x = 3

y = 2

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: