Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69.3 bpm. For a random sample of 140 adult males, the mean pulse rate is 69.8 bpm and the standard deviation is 11.2 bpm. Complete parts (a) and (b) below.

The question is find the test statistic

The test statistic is 0.5282

Step-by-step explanation:

Hypothesized mean u =69.3 , sample size (n) = 140, sample mean x = 69.8 ,  standard deviation s = 11.2

H₀: u = 69.3 bpm,  

Hₐ: u ≠ 69.3

The test statistic is given by = (x-u / (s/√n). Thus we have,

(69.8 - 69.3) / (11.2/√140)

  0.5 / (11.2/11.832)

= 0.5/0.9466

= 0.5282.

dnji

step-by-step explanation:

dskfbipo

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.