Solve using the quadratic frmula 2x^2-5x=3

3 and -1/2

Step-by-step explanation:

The quadratic formula is , for ax^2+bx+c=0.

You're equation is 2x^2-5x=3. Subtract 3 on both sides to get 2x^2-5x-3=0. Now we plug this in into the quadratic formula to get which is equal to There are 2 solutions, one being (5+7)/4= 12/4= 3, and the other being (5-7)/4=-2/4=-1/2/

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step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: