In the year 2019, Lee County used approximately 55 million gallons of water. Historical trends show that each year the water demand is increasing at a rate of approximately 2.1%. If this trend continues, approximately how many million gallons of water of water will be used by Lee County in the year 2025? Round to the nearest million.

To the nearest million, this is 62,000,000 gallons

Step-by-step explanation:

Here, we are to calculate the amount of water expected to be used by Lee County in the year 2025.

To calculate this amount, we set up an exponential function as follows;

A = I(1+r)^t

where A is the amount expected in the year 2025

I is the initial amount of water used which is 55 million

r is the percentage change per year which is 2.1% or simply 2.1/100 = 0.021

T is the difference in the years between 2025 and 2019 = 2025-2019 = 6 years

Plugging these values into the equation, we have

A = 55,000,000(1 + 0.021)^6

A = 55,000,000(1.021)^6

A = 62,304,173.899295434

To the nearest million, this is 62,000,000 gallons

it's both, now can you answer my most recent question?

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: