A bag contains 666 red jelly beans, 444 green jelly beans, and 444 blue jelly beans. If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red?

12/91

Step-by-step explanation:

The question is not properly formatted, here is how it should be formatted.

A bag contains 6red jelly beans, 4 green jelly beans, and 4 blue jelly beans. If we choose a jelly bean, then another jelly bean without putting the first one back in the bag, what is the probability that the first jelly bean will be green and the second will be red

Step one

This is selection without replacement.

Sample space

6red jelly beans,

4 green jelly beans, and

4 blue jelly beans.

S= 6+4+4= 14

Probability that the first jelly bean will be green = 4/14= 2/7

Without replacement, Probability that the second jelly bean will be red = 6/13

Hence for the two selections the probability is= 2/7*6/13= 12/91

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).

c(x)= 6x + 3

step-by-step explanation: