Suppose a triangle has two sides of length 33 and 37, and that the angle
between these two sides is 120°. Which equation should you solve to find the
length of the third side of the triangle?
A. c = 33+37 - 2(33) (37)cos 120°
B. 2 = 332 + 372 - 2(33)(37)sin120°
C.
sin33
120
sin37
b
D. 2 = 332 + 372 - 2(33)(37)cos120°

c^2=33^2+37^2-2(33)(37)cos120(i don't know for sure tho)

Step-by-step explanation:

LAW OF COSINES

The answer is: c^2=33^2+37^2-2(33)(37)cos120

Step-by-step explanation:

:D

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.