There are 130 people in a sports centre. 65 people use the gym 51 people use the swimming pool, 44 people use the track 15 people use the gym and the pool 14 people use the pool and the track 10 people use the gym and the track 1 person uses all 3 facilities A person is selected at random, what is the probability that this person doesn't use any facilities?

Step-by-step explanation:

The Venn diagram representing the situation is shown in the attached photo.

G represents the set of people that use the gym.

P represents the set of people that use the swimming pool.

T represents the set of people that use the track.

Since 1 person uses the 3 facilities, it means that

Number of persons that use gym and pool only is 15 - 1 = 14

Number of persons that use pool and track only is 14 - 1 = 13

Number of persons that use gym and track only is 10 - 1 = 9

Number of persons that use gym only is

65 - (14 + 1 + 9) = 41

Number of persons that use pool only is

51 - (14 + 1 + 13) = 23

Number of persons that use track only is

44 - (9 + 1 + 13) = 21

N represents the number of people that use none of the facilities. Since there are 130 people in a sports centre, it means that

41 + 23 + 21 + 9 + 14 + 13 + 1 + N = 130

122 + N = 130

N = 130 - 122

N = 8

Therefore, the probability that a person doesn't use any facilities is

8/130 = 0.062

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.