Factor out completly: 6x^2y − 3xy − 24xy^2 + 12y^2

The factor of 6x²y − 3xy − 24xy² + 12y² is 3y(2x - 1)(x - 4y)

Given:

6x²y − 3xy − 24xy² + 12y²

find the highest common factor of all the coefficient of each term

6 = 1, 2, 3, 6

6 = 1, 2, 3, 63 = 1, 3

6 = 1, 2, 3, 63 = 1, 324 = 1, 2, 3, 4, 6, 8, 12, 24

6 = 1, 2, 3, 63 = 1, 324 = 1, 2, 3, 4, 6, 8, 12, 2412 = 1, 2, 3, 4, 6, 8, 12

The highest common factor of all the coefficient of each term is 3

So,

6x²y − 3xy − 24xy² + 12y²

= 3y(2x² - x - 8xy + 4y)

(2x² - x - 8xy + 4y) = (2x - 1)(x - 4y)

Therefore,

6x²y − 3xy − 24xy² + 12y = 3y(2x - 1)(x - 4y)

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