Find the vertex I’d this parabola y=-2x^2-4x+4

  (-1, 6)

Step-by-step explanation:

A graphing calculator shows the vertex to be (x, y) = (-1, 6).

__

You can also find it by putting the equation into vertex form.

  y = -2(x^2 +2x) +4

  y = -2(x^2 +2x +1) +4 +2(1) . . . . . add 1 inside parens; the opposite outside

  y = -2(x +1)^2 +6

Compare to ...

  y = a(x -h)^2 +k

and you see a=-2, h=-1, k=6

The vertex is (h, k) = (-1, 6).

can you give me more detail on this! ?

step-by-step explanation:

good luck!

cutie~