A standard deck of playing cards has 13 cards in each of four suits: hearts, clubs, diamonds, and spades. Two cards are chosen from the deck at random. What is the probability of choosing one club and one spade?

a 1/2

b 13/204

c 13/102

d 15/102

13/102

Step-by-step explanation:

We will assume that order doesn't matter

P (club) =  number of clubs / total

                 13/52

Now we have 51 cards since we keep the card

P ( spade) =   number of spades / total

                     13/51

P(club, keep, spade) = 13/52 * 13/51 =13/204

But we also have the case of spade, club

P (spade) =  number of spade / total

                 13/52

Now we have 51 cards since we keep the card

P ( club) =   number of clubs / total

                     13/51

P(spade, keep, club) = 13/52 * 13/51 =13/204

Add the two together since it can be in either order

13/204+13/204

26/204 = 13/102

C

Step-by-step explanation:

13C1 × 13C1 / 52C2

169/1326

13/102

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you