Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. Assume that theta is the angle made by the positive x-axis and a ray from the origin

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

= side opposite to /hypotenuse

= side adjacent to /hypotenuse

So, coordinates of A =

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by

Put

So, satisfies the equation

For points   inside the circle,

For points   outside the circle,

So, only points on the circle satisfy the given inequality.

A. All of the unit circle

Step-by-step explanation:

Edge.

drop out of school or go to quizlet, quizlet is better

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)