Slope-intercept form for y = 3x – 5 :
Slope-intercept form for y - 3x = - 3:
Are the lines parallel or perpendicular?
a. Perpendicular
b. y = 3:- 5
ahl

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation:

step-by-step explanation:

20-2= what