You are running a race. The probability that you win is 3/5. What is the probability that you lose at most 2 out of your 6 races?

The probability that you lose at most 2 out of your 6 races is 0.54432.

Step-by-step explanation:

We are given that you are running a race. The probability that you win is 3/5.

There are total of 6 races.

The above situation can be represented through binomial distribution;

where, n = number of trials (samples) taken = 6 races

            r = number of success = at most 2 lost

            p = probability of success which in our question is probability that

                  you lose a race =  1 - (3/5) = 2/5 or 0.4

Let X = Number of races lost

So, X ~ Binom(n = 6, p = 0.40)

Now, the probability that you lose at most 2 out of your 6 races is given by = P(X 2)

P(X 2)  =  P(X = 0) + P(X = 1) + P(X = 2)

=    

=    

=  0.54432

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation: