Which parabola will have a minimum value vertex? On a coordinate plane, a parabola opens down with x-intercepts at (negative 2.2, 0) and (2.2, 0), and a y-intercept at the vertex (0, 5). On a coordinate plane, a parabola opens down with a vertex at (0, 0). On a coordinate plane, a parabola opens down with x-intercepts at (negative 1, 0) and (2.3, 0), a y-intercept at (0, 2), and has a vertex at (0.75, 2.5). On a coordinate plane, a parabola opens up with x-intercepts at (negative 2, 0) and (2, 0), and a y-intercept at the vertex (0, negative 4).

(D)On a coordinate plane, a parabola opens up with x-intercepts at (negative 2, 0) and (2, 0), and a y-intercept at the vertex (0, negative 4).

Step-by-step explanation:

For a parabola to have a minimum vertex, it must open upward. (a>0).

In the given options, the parabola which opens upward is option D.

On a coordinate plane, a parabola opens up with x-intercepts at (negative 2, 0) and (2, 0), and a y-intercept at the vertex (0, negative 4).

Therefore, it has a minimum vertex with coordinates (0,-4).

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

42.4

step-by-step explanation:

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