The length of a rectangle is four times it width. If the perimeter of the rectangle is 70 ft, find its length and width

length= 4w

width= w

perimeter= 2(l+w)

70= 2(4w+w)

70=8w+2w

70=10w

10. 10.

w= 7ft

l= 7×2

=56

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

i think 5 miles per hour

step-by-step explanation: