Write the standard equation of a circle with center (2, 1) and radius 8. The standard equation of the circle is...

In the Cartesian plane, the general standard equation for a circle with center (p,q) and radius r is

(x-p)² + (y-q)²  = r²

Here we have (p,q)=(2,1) and r=8 so our equation is

(x-2)²+(y-1)² = 8²

I guess we evaluate the 8².

(x-2)²+(y-1)² = 64

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative