PLS HELP WILL MARK BRAINLIEST
Given: 6(2x−2)≥3x+2(x+1)

Prove: x≥2
6(2x−2)≥3x+2(x+1)
Response area
12x−12≥3x+2x+2
Response area
12x−12≥5x+2
Response area
7x−12≥2
Response area
7x≥14
Response area
x≥2
Response area

i think its a and d

step-by-step explanation:

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)

ιт ωαѕ 5¢м вє¢αυѕє 1/4 σf 20 ιѕ 5

αи∂ 5*4=20

нσρє ι ¢συℓ∂ нєℓρ уσυ