(Pythagorean theorem)

The box above is 15 centimeters long, 4 centimeters wide, and 3 centimeters tall. What is the length of the diagonal S of the bottom side?

What is the length of the diagonal R of the box?

S ≈ 16.49 cm and R ≈ 16.76 cm

Step-by-step explanation:

We are given that:

Length = 16 cm

Width = 4 cm

Height = 3 cm

Thus,

The diagonal S of the bottom side is given by pythagoras theorem;

S² = 16² + 4²

S² = 256 + 16

S² = 272

S = √272

S ≈ 16.49 cm

Since we now have the bottom diagonal, then we can use Pythagoras Theorem to find the diagonal "R" of the box:

So, R² = S² + 3²

R² = (√272)² + 9

R² = 272 + 9

R = √281

R ≈ 16.76 cm

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus