On Saturday, some adults and some children were in a theatre. The ratio of the number of adults to the number of children was 5:2

Each person had a seat in the circle or has a seat in the stalls.

3/4 of children had seats in the stalls.

117 children has seats in the stalls.

There are exactly 2600 seats in the theatre. On this Saturday, we’re there people on more then 60% of the seats?

No, only 21% of the seats were occupied if 117 children had seats in the stall

Yes, more than 60% of the seats were occupied if if 117 children had seats in the circles.

Step-by-step explanation:

3/4 of children had seats in the stalls.

if  117 children has seats in the stalls.

Let the number of children be x, since 3/4 had seats in the stall, we have:

3/4*x = 3/4x.

The 3/4 fraction of children was 117.

= 3/4 of x = 117

= 3x/4 = 117

3x =117 x 4

3x = 468

x = 156 children in total.

117 children has seats in the stalls and 39 had seats in the circle

The ratio of the number of adults to the number of children was 5:2= 5+2=7

To find the total number of people: represent as y and use the ratio of children. Thus, we have

2/7 of y = 156

2y/7 = 156

2y = 156x7

2y= 1092

y = 546

Thus, the total number of people there are 546 and they occupy 546 seats out of 2600 seats. Thus we have:

546 / 2600 = 0.21 = 21%.

If 117 children had seats in the circle, then we have, 117 x 4 = 468 (total number of children)

Then using the ratio: 2/7 of y = 468 =     2y = 468x7

2y = 3276

y= 1,638

Thus, the total number of people there are 1,638 and they occupy 1,638 seats out of 2600 seats. Thus we have:

1638 / 2600 = 0.63 = 63%.

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

because they could drop even lower..