point v (8,10) is rotated 810 degrees counterclockwise about the origin. what is the x coordinate of the point after this rotation?

Step-by-step explanation:

A 810° rotation is equal to a 90° rotation. So, the transformation described gives the same result than rotating 90° only.

A 90° counterclockwise rotation is defined by the rule

The given coordinate is . Using the rule, we have

Therefore, the x-coordinate after the rotation is -10.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.