What is the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34 Round your answer to the nearest tenth of a percent!

A- 26.4%

B- 28.4%

C- 27.4%

D- 29.4%

We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.

The probability of a data score between two z-scores is given by formula .

Using above formula, we will get:

Now we will use normal distribution table to find probability corresponding to both z-scores as:

Now we will convert into percentage as:

Upon rounding to nearest tenth of percent, we will get:

Therefore, our required probability is 27.4% and option C is the correct choice.

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

if you was gonna solve for a, a is a   < -12