At a competition with 6 runners, medals are awarded for first, second, and

third places. Each of the 3 medals is different. How many ways are there to

award the medals?

Decide if this is a permutation or a combination, and find the number of ways

to award the medals.

O

A. Permutation; number of ways = 20

O

O

B. Combination; number of ways = 20

C. Permutation; number of ways = 120

O

D. Combination; number of ways = 120

SUBMIT

C. Permutation; number of ways = 120

Step-by-step explanation:

The order in which the runners finish is important. For example, A,B,C means that A will be awarded the 1st place medal, B the 2nd and C the 3rd. B,A,C means that B is awarded the 1st place medal, A the 2nd and C the 3rd. So we use the permutations formula to solve this question. That is, this is a permutation.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

In this question:

3 medals to 6 runners. So

So the correct answer is:

C. Permutation; number of ways = 120

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

if i put something wrong your not gonna like it so rather not say nothing.