Find the zeros of the function. Write the smaller solution first, and the larger solution second. f(x)=-3x^2 +75f(x)=−3x 2 +75f, left parenthesis, x, right parenthesis, equals, minus, 3, x, squared, plus, 75 \text{smaller }x =smaller x=start text, s, m, a, l, l, e, r, space, end text, x, equals \text{larger } x =larger x=start text, l, a, r, g, e, r, space, end text, x, equals

Step-by-step explanation:

Given the function

The zeros of the function are the values of x for which f(x)=0.

The zeros of f(x) are therefore 5 and -5.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb