Here are the first five terms of a sequence.

3 8 17 30

47

Find an expression, in terms of n, for the nth term of this sequence.

So the formula for the sequence is

Second term =first term + (a+nd)

Third term = second term + (a+nd)

And so on

Where n start with zero

Step-by-step explanation:

3 8 17 30 47

First term = 3

Second term = 8

Third term = 17

Fourth term = 30

Fifth term = 47

Second term - first term = 8-3=5

Third term - second term = 17-8= 9

Fourth term - third term = 30-17=13

Fifth term - fourth term = 47-30=17

So the AP is 5 9 13 17

We find out that the common difference is 9-5 = 4

The formula for nth term of the AP is

= a + nd

So the formula fir the sequence is

Second term =first term + (a+nd)

Third term = second term + (a+nd)

And so on

Where n start with zero

asdasd

step-by-step explanation:

step-by-step explanation:

descending order means to order the polynomials from the term with the largest exponent to the term with the smallest exponent.  

therefore, the correct answer is d.