6x^2 - 19x + 10
Factor

(2x-5)(3x-2)

Step-by-step explanation:

1)When factoring quadratic equations in for ax²+bx+c you need to separate the b term in a way that the two addends you separate it by should equal a•c. Just do trial and error. In this case you should get -4 and -15. Your separated equation should be:

6x²-4x-15x+10

2)now factor out a common factor from the first two terms and one from the last two terms you should have:

2x(3x-2)-5(3x-2)

3)finally rewrite this equation into two separate factors and you have your answer.

c. (3,2,6) is the answer.

y∈r, 8> y≥0

hope i !

p.s the first bit only matters if you know what that means.

p.p.s brainliest would really